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	<title>Comments on: Ep. 76: Lagrange Points</title>
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	<link>http://www.astronomycast.com/physics/ep-76-lagrange-points/</link>
	<description>Take a weekly facts-based journey through the cosmos with Astronomy Cast.</description>
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		<title>By: saksham</title>
		<link>http://www.astronomycast.com/physics/ep-76-lagrange-points/comment-page-1/#comment-623</link>
		<dc:creator>saksham</dc:creator>
		<pubDate>Mon, 04 Aug 2008 15:45:17 +0000</pubDate>
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		<description>i liked this episode alot, like all other episode. 
my question is..
are there lagrange point between sun and earth only or they can be between any two bodies. like earth and moon, or earth and mars. etc</description>
		<content:encoded><![CDATA[<p>i liked this episode alot, like all other episode.<br />
my question is..<br />
are there lagrange point between sun and earth only or they can be between any two bodies. like earth and moon, or earth and mars. etc</p>
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	<item>
		<title>By: Ty Dowding</title>
		<link>http://www.astronomycast.com/physics/ep-76-lagrange-points/comment-page-1/#comment-260</link>
		<dc:creator>Ty Dowding</dc:creator>
		<pubDate>Fri, 29 Feb 2008 17:29:35 +0000</pubDate>
		<guid isPermaLink="false">http://www.astronomycast.com/physics/ep-76-lagrange-points/#comment-260</guid>
		<description>Are there plans to use L4 &amp; L5 for a &quot;Binocular&quot; telescope(s). Seems like that would be capable of extreme parallaxes.</description>
		<content:encoded><![CDATA[<p>Are there plans to use L4 &amp; L5 for a &#034;Binocular&#034; telescope(s). Seems like that would be capable of extreme parallaxes.</p>
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	<item>
		<title>By: David Rust</title>
		<link>http://www.astronomycast.com/physics/ep-76-lagrange-points/comment-page-1/#comment-247</link>
		<dc:creator>David Rust</dc:creator>
		<pubDate>Wed, 20 Feb 2008 19:12:40 +0000</pubDate>
		<guid isPermaLink="false">http://www.astronomycast.com/physics/ep-76-lagrange-points/#comment-247</guid>
		<description>Good day,

So, given the discussion of LaGrange points, I&#039;m guessing that the old Science Fiction chestnut about a &quot;hidden planet&quot; on the far side of the sun -in the exact, corresponding orbit of Earth- wouldn&#039;t be possible.  The presence of another gravitational body in that position -so close to L3- would, essentially, totally re-position and &quot;cancel out&quot; the existing, observed L1-L5.

Would this assessment be correct?

Yours,
Dave</description>
		<content:encoded><![CDATA[<p>Good day,</p>
<p>So, given the discussion of LaGrange points, I&#039;m guessing that the old Science Fiction chestnut about a &#034;hidden planet&#034; on the far side of the sun -in the exact, corresponding orbit of Earth- wouldn&#039;t be possible.  The presence of another gravitational body in that position -so close to L3- would, essentially, totally re-position and &#034;cancel out&#034; the existing, observed L1-L5.</p>
<p>Would this assessment be correct?</p>
<p>Yours,<br />
Dave</p>
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		<title>By: mukut dave</title>
		<link>http://www.astronomycast.com/physics/ep-76-lagrange-points/comment-page-1/#comment-245</link>
		<dc:creator>mukut dave</dc:creator>
		<pubDate>Tue, 19 Feb 2008 16:06:29 +0000</pubDate>
		<guid isPermaLink="false">http://www.astronomycast.com/physics/ep-76-lagrange-points/#comment-245</guid>
		<description>Dear Sir : The Soho space craft circling the Sun is at one of the Langrangian points, but when I tried to compute the point of stability, I get a different number from where SOHO actually is , the computation is s follows.

             Mst     x Msun                                                 =        Mst   x    Mearth earth
           -------------------                                                  --------------------------

                 D2   (distance from SOHO to sun )                                       d2                 distnce from soho to earth</description>
		<content:encoded><![CDATA[<p>Dear Sir : The Soho space craft circling the Sun is at one of the Langrangian points, but when I tried to compute the point of stability, I get a different number from where SOHO actually is , the computation is s follows.</p>
<p>             Mst     x Msun                                                 =        Mst   x    Mearth earth<br />
           &#8212;&#8212;&#8212;&#8212;&#8212;&#8212;-                                                  &#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8211;</p>
<p>                 D2   (distance from SOHO to sun )                                       d2                 distnce from soho to earth</p>
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